What are the solutions to the equation (x-4)^2-25=0 ?

The solutions to the equation (x-4)^2-25=0 are x=9,x=-1

Find the zeros of (x-4)^2-25=0

The zeros of (x-4)^2-25=0 are x=9,x=-1

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(x - 4)^{2} - 25 = 0

x = 9, x = - 1

Solution steps

(x - 4)^{2} - 25 = 0

Move

25

to the right side

(x - 4)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 25 : x = 9

Solve

x - 4 = - 25 : x = - 1

The solutions to the quadratic equation are:

x = 9, x = - 1

5 + c - 3 \leq 6

144 a^{2} b^{4} c^{6}

8 p^{2} + 7 p

1 = x^{2} + 2 x - 1

x^{2} - 20 x + 75

What are the solutions to the equation (x-4)^2-25=0 ?
The solutions to the equation (x-4)^2-25=0 are x=9,x=-1
Find the zeros of (x-4)^2-25=0
The zeros of (x-4)^2-25=0 are x=9,x=-1