What are the solutions to the equation 3x^2+19x-14=0 ?

The solutions to the equation 3x^2+19x-14=0 are x= 2/3 ,x=-7

Find the zeros of 3x^2+19x-14=0

The zeros of 3x^2+19x-14=0 are x= 2/3 ,x=-7

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3 x^{2} + 19 x - 14 = 0

x = \frac{2}{3}, x = - 7

Decimal Notation

x = 0.66666 \dots, x = - 7

Solution steps

3 x^{2} + 19 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 3 ( - 14 )}{2 \cdot 3}

1 9^{2} - 4 \cdot 3 (- 14) = 23

x_{1, 2} = \frac{- 19 \pm 23}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 19 + 23}{2 \cdot 3}, x_{2} = \frac{- 19 - 23}{2 \cdot 3}

x = \frac{- 19 + 23}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 19 - 23}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 7

- \frac{1}{3} (3)

9 r^{2} + 24 r + 16

x^{2} + 6 x = 18

5 h - 4 \geq 6 and 7 h + 11 < 32

∣ 3 x - 1 ∣ = ∣ x + 2 ∣

What are the solutions to the equation 3x^2+19x-14=0 ?
The solutions to the equation 3x^2+19x-14=0 are x= 2/3 ,x=-7
Find the zeros of 3x^2+19x-14=0
The zeros of 3x^2+19x-14=0 are x= 2/3 ,x=-7