What are the solutions to the equation x^2-10=4x+4 ?

The solutions to the equation x^2-10=4x+4 are x=2+3sqrt(2),x=2-3sqrt(2)

Find the zeros of x^2-10=4x+4

The zeros of x^2-10=4x+4 are x=2+3sqrt(2),x=2-3sqrt(2)

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x^{2} - 10 = 4 x + 4

x = 2 + 32, x = 2 - 32

Decimal Notation

x = 6.24264 \dots, x = - 2.24264 \dots

Solution steps

x^{2} - 10 = 4 x + 4

Move

4

to the left side

x^{2} - 14 = 4 x

Move

4 x

to the left side

x^{2} - 14 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 14) = 62

x_{1, 2} = \frac{- ( - 4 ) \pm 6 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6 2}{2 \cdot 1} : 2 + 32

x = \frac{- ( - 4 ) - 6 2}{2 \cdot 1} : 2 - 32

The solutions to the quadratic equation are:

x = 2 + 32, x = 2 - 32

t^{2} - 10 t + 25 = 0

lo g_{10} (3)

4 a^{2} - 12 a + 9

\frac{8}{3}

s^{2} + 6 s - 16 = 0

What are the solutions to the equation x^2-10=4x+4 ?
The solutions to the equation x^2-10=4x+4 are x=2+3sqrt(2),x=2-3sqrt(2)
Find the zeros of x^2-10=4x+4
The zeros of x^2-10=4x+4 are x=2+3sqrt(2),x=2-3sqrt(2)