What are the solutions to the equation -3y^2-6y+2=0 ?

The solutions to the equation -3y^2-6y+2=0 are y=-(3+sqrt(15))/3 ,y=(sqrt(15)-3)/3

Find the zeros of -3y^2-6y+2=0

The zeros of -3y^2-6y+2=0 are y=-(3+sqrt(15))/3 ,y=(sqrt(15)-3)/3

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- 3 y^{2} - 6 y + 2 = 0

y = - \frac{3 + 15}{3}, y = \frac{15 - 3}{3}

Decimal Notation

y = - 2.29099 \dots, y = 0.29099 \dots

Solution steps

- 3 y^{2} - 6 y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 3 ) \cdot 2}{2 ( - 3 )}

(- 6)^{2} - 4 (- 3) \cdot 2 = 215

y_{1, 2} = \frac{- ( - 6 ) \pm 2 15}{2 ( - 3 )}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 2 15}{2 ( - 3 )}, y_{2} = \frac{- ( - 6 ) - 2 15}{2 ( - 3 )}

y = \frac{- ( - 6 ) + 2 15}{2 ( - 3 )} : - \frac{3 + 15}{3}

y = \frac{- ( - 6 ) - 2 15}{2 ( - 3 )} : \frac{15 - 3}{3}

The solutions to the quadratic equation are:

y = - \frac{3 + 15}{3}, y = \frac{15 - 3}{3}

3 (u + 2) + u = 4 (u - 1) + 10

h^{2} + 6 h - 5 = 0

- 9 x + 2 > 18 and 13 x + 15 \leq - 4

0 = x^{2} + 16 x - 5

2 x + 7 = - 11

What are the solutions to the equation -3y^2-6y+2=0 ?
The solutions to the equation -3y^2-6y+2=0 are y=-(3+sqrt(15))/3 ,y=(sqrt(15)-3)/3
Find the zeros of -3y^2-6y+2=0
The zeros of -3y^2-6y+2=0 are y=-(3+sqrt(15))/3 ,y=(sqrt(15)-3)/3