What are the solutions to the equation s^2+8s+12=0 ?

The solutions to the equation s^2+8s+12=0 are s=-2,s=-6

Find the zeros of s^2+8s+12=0

The zeros of s^2+8s+12=0 are s=-2,s=-6

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s^{2} + 8 s + 12 = 0

s = - 2, s = - 6

Solution steps

s^{2} + 8 s + 12 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 12 = 4

s_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 8 + 4}{2 \cdot 1}, s_{2} = \frac{- 8 - 4}{2 \cdot 1}

s = \frac{- 8 + 4}{2 \cdot 1} : - 2

s = \frac{- 8 - 4}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

s = - 2, s = - 6

3 x^{2} - 6 x - 18 = 0

5 \cdot \frac{1}{4}

(\frac{2}{5})^{- 3}

(2 x^{2} y^{4}) + (2 x y) - (3 x^{2} y^{2})

21 + 4 (3^{2} - 5)

What are the solutions to the equation s^2+8s+12=0 ?
The solutions to the equation s^2+8s+12=0 are s=-2,s=-6
Find the zeros of s^2+8s+12=0
The zeros of s^2+8s+12=0 are s=-2,s=-6