What are the solutions to the equation 7x^2-12x-4=0 ?

The solutions to the equation 7x^2-12x-4=0 are x=2,x=-2/7

Find the zeros of 7x^2-12x-4=0

The zeros of 7x^2-12x-4=0 are x=2,x=-2/7

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7 x^{2} - 12 x - 4 = 0

x = 2, x = - \frac{2}{7}

Decimal Notation

x = 2, x = - 0.28571 \dots

Solution steps

7 x^{2} - 12 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 7 ( - 4 )}{2 \cdot 7}

(- 12)^{2} - 4 \cdot 7 (- 4) = 16

x_{1, 2} = \frac{- ( - 12 ) \pm 16}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 16}{2 \cdot 7}, x_{2} = \frac{- ( - 12 ) - 16}{2 \cdot 7}

x = \frac{- ( - 12 ) + 16}{2 \cdot 7} : 2

x = \frac{- ( - 12 ) - 16}{2 \cdot 7} : - \frac{2}{7}

The solutions to the quadratic equation are:

x = 2, x = - \frac{2}{7}

3 p + 13 = 37

5 x^{2} + 8 x + 15 = 0

(4 + i) (3 + 2 i) (1 - i)

\frac{3}{2} + \frac{1}{3} - \frac{1}{4}

x^{2} - 1 \leq ∣ x + 1 ∣

What are the solutions to the equation 7x^2-12x-4=0 ?
The solutions to the equation 7x^2-12x-4=0 are x=2,x=-2/7
Find the zeros of 7x^2-12x-4=0
The zeros of 7x^2-12x-4=0 are x=2,x=-2/7