What are the solutions to the equation 7x^2-14x+5=-x^2 ?

The solutions to the equation 7x^2-14x+5=-x^2 are x= 5/4 ,x= 1/2

Find the zeros of 7x^2-14x+5=-x^2

The zeros of 7x^2-14x+5=-x^2 are x= 5/4 ,x= 1/2

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7 x^{2} - 14 x + 5 = - x^{2}

x = \frac{5}{4}, x = \frac{1}{2}

Solution steps

7 x^{2} - 14 x + 5 = - x^{2}

Move

x^{2}

to the left side

8 x^{2} - 14 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 8 \cdot 5}{2 \cdot 8}

(- 14)^{2} - 4 \cdot 8 \cdot 5 = 6

x_{1, 2} = \frac{- ( - 14 ) \pm 6}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 6}{2 \cdot 8}, x_{2} = \frac{- ( - 14 ) - 6}{2 \cdot 8}

x = \frac{- ( - 14 ) + 6}{2 \cdot 8} : \frac{5}{4}

x = \frac{- ( - 14 ) - 6}{2 \cdot 8} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = \frac{1}{2}

a^{2} + 5 a - 14

\frac{4 x ^{- 2}}{y ^{- 8}}

12 x - 4 (5 x - 1) = 3 - 4 x

- 0.375 c - 11 = 13

4160 + 240

What are the solutions to the equation 7x^2-14x+5=-x^2 ?
The solutions to the equation 7x^2-14x+5=-x^2 are x= 5/4 ,x= 1/2
Find the zeros of 7x^2-14x+5=-x^2
The zeros of 7x^2-14x+5=-x^2 are x= 5/4 ,x= 1/2