What are the solutions to the equation 3y^2=12y ?

The solutions to the equation 3y^2=12y are y=0,y=4

Find the zeros of 3y^2=12y

The zeros of 3y^2=12y are y=0,y=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 y^{2} = 12 y

y = 0, y = 4

Solution steps

3 y^{2} = 12 y

Move

12 y

to the left side

3 y^{2} - 12 y = 0

Factor

3 y^{2} - 12 y : 3 y (y - 4)

3 y (y - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or y - 4 = 0

Solve

y - 4 = 0 : y = 4

The solutions to the quadratic equation are:

y = 0, y = 4

\frac{1}{2} p + 7 = \frac{3}{4} p + 9

\frac{x}{2} + \frac{x}{3} = 10

\frac{27}{2} - 8

a y - 3 b y + 3 a z - 9 b z

\frac{x - 18}{2} \geq \frac{x - 9}{3} + \frac{5}{6}

What are the solutions to the equation 3y^2=12y ?
The solutions to the equation 3y^2=12y are y=0,y=4
Find the zeros of 3y^2=12y
The zeros of 3y^2=12y are y=0,y=4