What are the solutions to the equation y^2+9y+20=0 ?

The solutions to the equation y^2+9y+20=0 are y=-4,y=-5

Find the zeros of y^2+9y+20=0

The zeros of y^2+9y+20=0 are y=-4,y=-5

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y^{2} + 9 y + 20 = 0

y = - 4, y = - 5

Solution steps

y^{2} + 9 y + 20 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

y_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 9 + 1}{2 \cdot 1}, y_{2} = \frac{- 9 - 1}{2 \cdot 1}

y = \frac{- 9 + 1}{2 \cdot 1} : - 4

y = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

y = - 4, y = - 5

718

\frac{x}{- 3} - 1 \leq 5

4 x^{2} + 12 x - 27 = 0

4^{\frac{1}{4}}

9 y^{2} + 25 = - 30 y

What are the solutions to the equation y^2+9y+20=0 ?
The solutions to the equation y^2+9y+20=0 are y=-4,y=-5
Find the zeros of y^2+9y+20=0
The zeros of y^2+9y+20=0 are y=-4,y=-5