What are the solutions to the equation 4x^2-15x-1=0 ?

The solutions to the equation 4x^2-15x-1=0 are x=(15+sqrt(241))/8 ,x=(15-sqrt(241))/8

Find the zeros of 4x^2-15x-1=0

The zeros of 4x^2-15x-1=0 are x=(15+sqrt(241))/8 ,x=(15-sqrt(241))/8

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4 x^{2} - 15 x - 1 = 0

x = \frac{15 + 241}{8}, x = \frac{15 - 241}{8}

Decimal Notation

x = 3.81552 \dots, x = - 0.06552 \dots

Solution steps

4 x^{2} - 15 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

(- 15)^{2} - 4 \cdot 4 (- 1) = 241

x_{1, 2} = \frac{- ( - 15 ) \pm 241}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 241}{2 \cdot 4}, x_{2} = \frac{- ( - 15 ) - 241}{2 \cdot 4}

x = \frac{- ( - 15 ) + 241}{2 \cdot 4} : \frac{15 + 241}{8}

x = \frac{- ( - 15 ) - 241}{2 \cdot 4} : \frac{15 - 241}{8}

The solutions to the quadratic equation are:

x = \frac{15 + 241}{8}, x = \frac{15 - 241}{8}

∣ 3 x + 2 ∣ = ∣ 2 x + 23 ∣

7 (3 - 2 x) + 2 (2 x - 15) < 2 (5 x - 7) - 3 (2 x - 11)

∣ v + 8 ∣ - 5 = 2

\frac{( 2 x ^{3} y ^{0} ) ^{4}}{x ^{9}}

8 x^{2} - 2 x = 3

What are the solutions to the equation 4x^2-15x-1=0 ?
The solutions to the equation 4x^2-15x-1=0 are x=(15+sqrt(241))/8 ,x=(15-sqrt(241))/8
Find the zeros of 4x^2-15x-1=0
The zeros of 4x^2-15x-1=0 are x=(15+sqrt(241))/8 ,x=(15-sqrt(241))/8