What are the solutions to the equation x^2+8x=88 ?

The solutions to the equation x^2+8x=88 are x=2(sqrt(26)-2),x=-2(2+sqrt(26))

Find the zeros of x^2+8x=88

The zeros of x^2+8x=88 are x=2(sqrt(26)-2),x=-2(2+sqrt(26))

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x^{2} + 8 x = 88

x = 2 (26 - 2), x = - 2 (2 + 26)

Decimal Notation

x = 6.19803 \dots, x = - 14.19803 \dots

Solution steps

x^{2} + 8 x = 88

Move

88

to the left side

x^{2} + 8 x - 88 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 88 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 88) = 426

x_{1, 2} = \frac{- 8 \pm 4 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 4 26}{2 \cdot 1}, x_{2} = \frac{- 8 - 4 26}{2 \cdot 1}

x = \frac{- 8 + 4 26}{2 \cdot 1} : 2 (26 - 2)

x = \frac{- 8 - 4 26}{2 \cdot 1} : - 2 (2 + 26)

The solutions to the quadratic equation are:

x = 2 (26 - 2), x = - 2 (2 + 26)

(- 2 g^{2} h)^{3} (\frac{g}{4 h ^{2}})^{2}

5 n^{2} = 9 n

\frac{1}{n ^{7} \cdot n ^{- 5}}

- \frac{6}{6}

\frac{3}{2} - \frac{2}{3}

What are the solutions to the equation x^2+8x=88 ?
The solutions to the equation x^2+8x=88 are x=2(sqrt(26)-2),x=-2(2+sqrt(26))
Find the zeros of x^2+8x=88
The zeros of x^2+8x=88 are x=2(sqrt(26)-2),x=-2(2+sqrt(26))