What are the solutions to the equation x=2x^2 ?

The solutions to the equation x=2x^2 are x= 1/2 ,x=0

Find the zeros of x=2x^2

The zeros of x=2x^2 are x= 1/2 ,x=0

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x = 2 x^{2}

x = \frac{1}{2}, x = 0

Decimal Notation

x = 0.5, x = 0

Solution steps

x = 2 x^{2}

Switch sides

2 x^{2} = x

Move

x

to the left side

2 x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 2}

x = \frac{- ( - 1 ) + 1}{2 \cdot 2} : \frac{1}{2}

x = \frac{- ( - 1 ) - 1}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 0

\frac{6 - 3}{- 1 - 2}

2 - 8200

\frac{x}{x - 1} \leq 2

9 + \frac{9}{2}

What are the solutions to the equation x=2x^2 ?
The solutions to the equation x=2x^2 are x= 1/2 ,x=0
Find the zeros of x=2x^2
The zeros of x=2x^2 are x= 1/2 ,x=0