What are the solutions to the equation 25x^2-20x+4=0 ?

The solutions to the equation 25x^2-20x+4=0 are x= 2/5

Find the zeros of 25x^2-20x+4=0

The zeros of 25x^2-20x+4=0 are x= 2/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25 x^{2} - 20 x + 4 = 0

x = \frac{2}{5}

Decimal Notation

x = 0.4

Solution steps

25 x^{2} - 20 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 25 \cdot 4}{2 \cdot 25}

(- 20)^{2} - 4 \cdot 25 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 20 )}{2 \cdot 25}

\frac{- ( - 20 )}{2 \cdot 25} = \frac{2}{5}

x = \frac{2}{5}

The solution to the quadratic equation is:

x = \frac{2}{5}

\frac{x}{\frac{y}{x}}

- 8 a + 4 = - 180

7 - 4

215 = 11 - y

∣ y ∣ - 2 = 0

What are the solutions to the equation 25x^2-20x+4=0 ?
The solutions to the equation 25x^2-20x+4=0 are x= 2/5
Find the zeros of 25x^2-20x+4=0
The zeros of 25x^2-20x+4=0 are x= 2/5