What are the solutions to the equation x^2+5x-21=0 ?

The solutions to the equation x^2+5x-21=0 are x=(-5+sqrt(109))/2 ,x=(-5-sqrt(109))/2

Find the zeros of x^2+5x-21=0

The zeros of x^2+5x-21=0 are x=(-5+sqrt(109))/2 ,x=(-5-sqrt(109))/2

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x^{2} + 5 x - 21 = 0

x = \frac{- 5 + 109}{2}, x = \frac{- 5 - 109}{2}

Decimal Notation

x = 2.72015 \dots, x = - 7.72015 \dots

Solution steps

x^{2} + 5 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 21) = 109

x_{1, 2} = \frac{- 5 \pm 109}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 109}{2 \cdot 1}, x_{2} = \frac{- 5 - 109}{2 \cdot 1}

x = \frac{- 5 + 109}{2 \cdot 1} : \frac{- 5 + 109}{2}

x = \frac{- 5 - 109}{2 \cdot 1} : \frac{- 5 - 109}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 109}{2}, x = \frac{- 5 - 109}{2}

\frac{x ^{2} y ^{- 5}}{x ^{- 8} y ^{- 8}}

2 x - 1 = 3 x + 8

\frac{2 n ^{2}}{n}

x^{2} - 4 x + 148 = 0

(4 - 3 i) (4 + 3 i)

What are the solutions to the equation x^2+5x-21=0 ?
The solutions to the equation x^2+5x-21=0 are x=(-5+sqrt(109))/2 ,x=(-5-sqrt(109))/2
Find the zeros of x^2+5x-21=0
The zeros of x^2+5x-21=0 are x=(-5+sqrt(109))/2 ,x=(-5-sqrt(109))/2