What are the solutions to the equation v^2=12v ?

The solutions to the equation v^2=12v are v=12,v=0

Find the zeros of v^2=12v

The zeros of v^2=12v are v=12,v=0

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v^{2} = 12 v

v = 12, v = 0

Solution steps

v^{2} = 12 v

Move

12 v

to the left side

v^{2} - 12 v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 0 = 12

v_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 1}, v_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 1}

v = \frac{- ( - 12 ) + 12}{2 \cdot 1} : 12

v = \frac{- ( - 12 ) - 12}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

v = 12, v = 0

27 n^{2} - 54 n + 15

y^{2} (y + 5) - 16 (y + 5)

2 b - 5 = 2 (4 b - 1) + 20

0 = 3 x^{2} - x - 10

6 (3 x + 9) - 8 x \leq - 6

What are the solutions to the equation v^2=12v ?
The solutions to the equation v^2=12v are v=12,v=0
Find the zeros of v^2=12v
The zeros of v^2=12v are v=12,v=0