What are the solutions to the equation 2r^2+4r+2=0 ?

The solutions to the equation 2r^2+4r+2=0 are r=-1

Find the zeros of 2r^2+4r+2=0

The zeros of 2r^2+4r+2=0 are r=-1

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2 r^{2} + 4 r + 2 = 0

r = - 1

Solution steps

2 r^{2} + 4 r + 2 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

4^{2} - 4 \cdot 2 \cdot 2 = 0

r_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 2}

r = \frac{- 4}{2 \cdot 2}

\frac{- 4}{2 \cdot 2} = - 1

r = - 1

The solution to the quadratic equation is:

r = - 1

3 x^{2} = - 4 + 8 x

3 k^{3} + 6 k^{2}

7 x + 4 = 28

(x^{2} - 7 x) = 0

\frac{4}{5} - \frac{2}{3}

What are the solutions to the equation 2r^2+4r+2=0 ?
The solutions to the equation 2r^2+4r+2=0 are r=-1
Find the zeros of 2r^2+4r+2=0
The zeros of 2r^2+4r+2=0 are r=-1