What are the solutions to the equation 2x^2=7x-5 ?

The solutions to the equation 2x^2=7x-5 are x= 5/2 ,x=1

Find the zeros of 2x^2=7x-5

The zeros of 2x^2=7x-5 are x= 5/2 ,x=1

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2 x^{2} = 7 x - 5

x = \frac{5}{2}, x = 1

Decimal Notation

x = 2.5, x = 1

Solution steps

2 x^{2} = 7 x - 5

Move

5

to the left side

2 x^{2} + 5 = 7 x

Move

7 x

to the left side

2 x^{2} + 5 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 7 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 \cdot 5 = 3

x_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 2}

x = \frac{- ( - 7 ) + 3}{2 \cdot 2} : \frac{5}{2}

x = \frac{- ( - 7 ) - 3}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = 1

4 n - 1 = 11

\frac{( 0.23094 ) ( 2.2 )}{4.6}

7 96 m^{3}

\frac{1}{3} \cdot \frac{5}{3}

\frac{- 4 - 2 i}{1 - i}

What are the solutions to the equation 2x^2=7x-5 ?
The solutions to the equation 2x^2=7x-5 are x= 5/2 ,x=1
Find the zeros of 2x^2=7x-5
The zeros of 2x^2=7x-5 are x= 5/2 ,x=1