What is factor x^4+2-3 ?

The solution to factor x^4+2-3 is (x^2+1)(x+1)(x-1)

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factor x^4+2-3

factor

x^{4} + 2 - 3

(x^{2} + 1) (x + 1) (x - 1)

Solution steps

x^{4} + 2 - 3

Add/Subtract the numbers:

2 - 3 = - 1

= x^{4} - 1

Rewrite

x^{4} - 1

(x^{2})^{2} - 1^{2}

= (x^{2})^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x^{2})^{2} - 1^{2} = (x^{2} + 1) (x^{2} - 1)

= (x^{2} + 1) (x^{2} - 1)

Factor

x^{2} - 1 : (x + 1) (x - 1)

= (x^{2} + 1) (x + 1) (x - 1)

8 b = 56

∣ 2 x + 1 ∣ < 13

- 6 (v + 1) = 2 (1 - 3 v) - 7

4 + 1.5 p = 35

(4 + 53)^{2}