What is ((x^2-5x+4)/(x^2)}{\frac{x-1)/x} ?

The solution to ((x^2-5x+4)/(x^2)}{\frac{x-1)/x} is (x-4)/x

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simplify ((x^2-5x+4)/(x^2)}{\frac{x-1)/x}

simplify

\frac{\frac{x ^{2} - 5 x + 4}{x ^{2}}}{\frac{x - 1}{x}}

\frac{x - 4}{x}

Solution steps

\frac{\frac{x ^{2} - 5 x + 4}{x ^{2}}}{\frac{x - 1}{x}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} - 5 x + 4 ) x}{x ^{2} ( x - 1 )}

Cancel

\frac{( x ^{2} - 5 x + 4 ) x}{x ^{2} ( x - 1 )} : \frac{x - 4}{x}

= \frac{x - 4}{x}

4 (2 x + 3)

4 (2 x + 1)

5 (- 4)

3 \cdot 1 0^{4}

\frac{24}{- 6}

What is ((x^2-5x+4)/(x^2)}{\frac{x-1)/x} ?
The solution to ((x^2-5x+4)/(x^2)}{\frac{x-1)/x} is (x-4)/x