What is (6x^2-384)/(4x^2-40x+64)*(x^2-4)/(x+8) ?

The solution to (6x^2-384)/(4x^2-40x+64)*(x^2-4)/(x+8) is (3(x+2))/2

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simplify (6x^2-384)/(4x^2-40x+64)*(x^2-4)/(x+8)

simplify

\frac{6 x ^{2} - 384}{4 x ^{2} - 40 x + 64} \cdot \frac{x ^{2} - 4}{x + 8}

\frac{3 ( x + 2 )}{2}

Solution steps

\frac{6 x ^{2} - 384}{4 x ^{2} - 40 x + 64} \cdot \frac{x ^{2} - 4}{x + 8}

Cancel

\frac{6 x ^{2} - 384}{4 x ^{2} - 40 x + 64} : \frac{3 ( x + 8 )}{2 ( x - 2 )}

= \frac{3 ( x + 8 )}{2 ( x - 2 )} \cdot \frac{x ^{2} - 4}{x + 8}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 ( x + 8 ) ( x ^{2} - 4 )}{2 ( x - 2 ) ( x + 8 )}

Cancel the common factor:

x + 8

= \frac{3 ( x ^{2} - 4 )}{2 ( x - 2 )}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{3 ( x + 2 ) ( x - 2 )}{2 ( x - 2 )}

Cancel the common factor:

x - 2

= \frac{3 ( x + 2 )}{2}

\frac{( 4 x ^{3} y ) ( 2 x ^{4} y ^{2} )}{2 x ^{3} y}

\frac{x}{\frac{3}{x} + \frac{1}{x}}

\frac{( 4 h ^{4} ) ^{3}}{2 h ^{5}}

4 x^{2} - 20 x y

(x^{2} - x - 2)^{2}

What is (6x^2-384)/(4x^2-40x+64)*(x^2-4)/(x+8) ?
The solution to (6x^2-384)/(4x^2-40x+64)*(x^2-4)/(x+8) is (3(x+2))/2