What is 2^2*3^4*2^{-1}*3^{-2} ?

The solution to 2^2*3^4*2^{-1}*3^{-2} is 18

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 2^23^42^{-1}*3^{-2}

simplify

2^{2} \cdot 3^{4} \cdot 2^{- 1} \cdot 3^{- 2}

18

Solution steps

2^{2} \cdot 3^{4} \cdot 2^{- 1} \cdot 3^{- 2}

2^{2} \cdot 2^{- 1} = 2

= 2 \cdot 3^{4} \cdot 3^{- 2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

3^{4} \cdot 3^{- 2} = 3^{4 - 2}

= 2 \cdot 3^{4 - 2}

Subtract the numbers:

4 - 2 = 2

= 2 \cdot 3^{2}

3^{2} = 9

= 2 \cdot 9

Multiply the numbers:

2 \cdot 9 = 18

= 18

\frac{\frac{x + 1}{x - 1} + 1}{\frac{x + 1}{x - 1} - 1}

\frac{72}{16}

- 0 + 2

(- 8 x^{2} + 3) + (- 9 x^{2} + 3 x - 3)

\frac{5 ^{2}}{5 ^{3}}