What is ((3x^2+4x-x^4-2x^3-4))/((x+2)) ?

The solution to ((3x^2+4x-x^4-2x^3-4))/((x+2)) is -(x-1)^2(x+2)

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simplify ((3x^2+4x-x^4-2x^3-4))/((x+2))

simplify

\frac{( 3 x ^{2} + 4 x - x ^{4} - 2 x ^{3} - 4 )}{( x + 2 )}

- (x - 1)^{2} (x + 2)

Solution steps

\frac{3 x ^{2} + 4 x - x ^{4} - 2 x ^{3} - 4}{x + 2}

Factor

3 x^{2} + 4 x - x^{4} - 2 x^{3} - 4 : - (x - 1)^{2} (x + 2)^{2}

= \frac{- ( x - 1 ) ^{2} ( x + 2 ) ^{2}}{x + 2}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x + 2)^{2} = (x + 2) (x + 2)

= \frac{- ( x - 1 ) ^{2} ( x + 2 ) ( x + 2 )}{x + 2}

Cancel the common factor:

x + 2

= - (x - 1)^{2} (x + 2)

\frac{( 4 t ) ^{4}}{5 t}

\frac{1}{4} \times 12

\frac{1}{8 x} + \frac{8}{3 x}

5 i (3 + i)

(\frac{x ^{4}}{2} - \frac{1}{2 x ^{4}})^{2}

What is ((3x^2+4x-x^4-2x^3-4))/((x+2)) ?
The solution to ((3x^2+4x-x^4-2x^3-4))/((x+2)) is -(x-1)^2(x+2)