What is expand (2x-3)(4x^2+6x+9) ?

The solution to expand (2x-3)(4x^2+6x+9) is 8x^3-27

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expand (2x-3)(4x^2+6x+9)

expand

(2 x - 3) (4 x^{2} + 6 x + 9)

8 x^{3} - 27

Solution steps

(2 x - 3) (4 x^{2} + 6 x + 9)

Distribute parentheses

= 2 x \cdot 4 x^{2} + 2 x \cdot 6 x + 2 x \cdot 9 - 3 \cdot 4 x^{2} - 3 \cdot 6 x - 3 \cdot 9

Simplify

2 x \cdot 4 x^{2} + 2 x \cdot 6 x + 2 x \cdot 9 - 3 \cdot 4 x^{2} - 3 \cdot 6 x - 3 \cdot 9 : 8 x^{3} - 27

= 8 x^{3} - 27

- 18 \div 3

f (9)

\frac{16 x ^{2} - 16 x}{4 x ^{3}}

lo g_{e} (- 1)

5 - 3

What is expand (2x-3)(4x^2+6x+9) ?
The solution to expand (2x-3)(4x^2+6x+9) is 8x^3-27