What is (\frac{x^2)/(x^2-x-42)}{(5x)/(x^2-36)} ?

The solution to (\frac{x^2)/(x^2-x-42)}{(5x)/(x^2-36)} is (x(x-6))/(5(x-7))

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simplify (\frac{x^2)/(x^2-x-42)}{(5x)/(x^2-36)}

simplify

\frac{\frac{x ^{2}}{x ^{2} - x - 42}}{\frac{5 x}{x ^{2} - 36}}

\frac{x ( x - 6 )}{5 ( x - 7 )}

Solution steps

\frac{\frac{x ^{2}}{x ^{2} - x - 42}}{\frac{5 x}{x ^{2} - 36}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{x ^{2} ( x ^{2} - 36 )}{( x ^{2} - x - 42 ) \cdot 5 x}

Cancel

\frac{x ^{2} ( x ^{2} - 36 )}{( x ^{2} - x - 42 ) \cdot 5 x} : \frac{x ( x - 6 )}{( x - 7 ) \cdot 5}

= \frac{x ( x - 6 )}{( x - 7 ) \cdot 5}

= \frac{x ( x - 6 )}{5 ( x - 7 )}

(3 x + 3) (3 x + 8)

8 a + 9 a

(1 - 2 i) (3 + 2 i) (5 + 2 i)

\frac{x ^{4} - y ^{4}}{x ^{2} - y ^{2}}

\frac{( 2 n ) !}{( 2 n + 1 ) !}

What is (\frac{x^2)/(x^2-x-42)}{(5x)/(x^2-36)} ?
The solution to (\frac{x^2)/(x^2-x-42)}{(5x)/(x^2-36)} is (x(x-6))/(5(x-7))