What are the solutions to the equation 0=x^2-5x+4 ?

The solutions to the equation 0=x^2-5x+4 are x=4,x=1

Find the zeros of 0=x^2-5x+4

The zeros of 0=x^2-5x+4 are x=4,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} - 5 x + 4

x = 4, x = 1

Solution steps

0 = x^{2} - 5 x + 4

Switch sides

x^{2} - 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

x = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

x = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 4, x = 1

8 + 2 t = 4 + 3 t

x^{3} - y^{6}

4 x^{2} + 6 x = 8

\frac{5 x}{6} - \frac{7}{4} + \frac{2 x}{3} = 2 x - \frac{5}{12} + \frac{x}{3}

w^{2} + 3 w = 40

What are the solutions to the equation 0=x^2-5x+4 ?
The solutions to the equation 0=x^2-5x+4 are x=4,x=1
Find the zeros of 0=x^2-5x+4
The zeros of 0=x^2-5x+4 are x=4,x=1