What is (4-10i)/(-3-7i) ?

The solution to (4-10i)/(-3-7i) is 1+i

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simplify (4-10i)/(-3-7i)

simplify

\frac{4 - 10 i}{- 3 - 7 i}

1 + i

Solution steps

\frac{4 - 10 i}{- 3 - 7 i}

Multiply by the conjugate

\frac{- 3 + 7 i}{- 3 + 7 i}

= \frac{( 4 - 10 i ) ( - 3 + 7 i )}{( - 3 - 7 i ) ( - 3 + 7 i )}

Simplify

\frac{( 4 - 10 i ) ( - 3 + 7 i )}{( - 3 - 7 i ) ( - 3 + 7 i )} : \frac{58 + 58 i}{58}

= \frac{58 + 58 i}{58}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{58}{58} + \frac{58}{58} i

Simplify

\frac{58}{58} + \frac{58}{58} i : 1 + i

= 1 + i

(\frac{5}{7})^{0}

\frac{ln ( x )}{x}

\frac{2 - x}{x ^{2} + 4 x - 12}

\frac{41}{3} \div \frac{22}{5}

\frac{\frac{x}{x + 1}}{\frac{x}{x + 1} + 1}