What is 1/i-(3+2i)/(2-i) ?

The solution to 1/i-(3+2i)/(2-i) is -4/5-12/5 i

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simplify 1/i-(3+2i)/(2-i)

simplify

\frac{1}{i} - \frac{3 + 2 i}{2 - i}

- \frac{4}{5} - \frac{12}{5} i

Solution steps

\frac{1}{i} - \frac{3 + 2 i}{2 - i}

\frac{1}{i} = - i

\frac{3 + 2 i}{2 - i} = \frac{4 + 7 i}{5}

= - i - \frac{4 + 7 i}{5}

Join

- i - \frac{4 + 7 i}{5} : \frac{- 12 i - 4}{5}

= \frac{- 12 i - 4}{5}

Rewrite in standard complex form:

- \frac{4}{5} - \frac{12}{5} i

= - \frac{4}{5} - \frac{12}{5} i

(2 x^{2} + 3 y)^{3}

- 8 \times 3

\frac{100}{3}

\frac{( x ^{2} - 4 )}{( x - 2 )}

x^{3} \cdot 2 x