simplify 3i(-2+4i)

Solution

simplify

3 i (- 2 + 4 i)

- 12 - 6 i

Solution steps

3 i (- 2 + 4 i)

Apply the distributive law:

a (b + c) = ab + a c

3 i (- 2 + 4 i) = 3 i (- 2) + 3 i 4 i

= 3 i (- 2) + 3 i 4 i

3 i (- 2) = - 6 i

3 i 4 i = - 12

= - 6 i - 12

Rewrite in standard complex form:

- 12 - 6 i

= - 12 - 6 i

(21 + 9 i) - (13 - 2 i)

\frac{1}{20} + \frac{1}{5}

\frac{\frac{7}{9}}{\frac{4}{3} + \frac{8}{12} \cdot \frac{2}{5}}

3 x^{2} + 8 x

(6 a^{3} b^{2} - 7 a^{2} b^{3} + 4 a b^{5}) (4 a^{5} b^{2})