What is expand (5x-4)(2x^2-3x-7) ?

The solution to expand (5x-4)(2x^2-3x-7) is 10x^3-23x^2-23x+28

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expand (5x-4)(2x^2-3x-7)

expand

(5 x - 4) (2 x^{2} - 3 x - 7)

10 x^{3} - 23 x^{2} - 23 x + 28

Solution steps

(5 x - 4) (2 x^{2} - 3 x - 7)

Distribute parentheses

= 5 x \cdot 2 x^{2} + 5 x (- 3 x) + 5 x (- 7) - 4 \cdot 2 x^{2} - 4 (- 3 x) - 4 (- 7)

Simplify

5 x \cdot 2 x^{2} + 5 x (- 3 x) + 5 x (- 7) - 4 \cdot 2 x^{2} - 4 (- 3 x) - 4 (- 7) : 10 x^{3} - 23 x^{2} - 23 x + 28

= 10 x^{3} - 23 x^{2} - 23 x + 28

\frac{22}{11}

2 (0.5)

\frac{a}{3 a + 6} - \frac{1}{6 a + 12} + \frac{a + 12}{12 a + 24}

7 \cdot 18

What is expand (5x-4)(2x^2-3x-7) ?
The solution to expand (5x-4)(2x^2-3x-7) is 10x^3-23x^2-23x+28