What is (2u+3)(u-4)+4u(u-2) ?

The solution to (2u+3)(u-4)+4u(u-2) is 6u^2-13u-12

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simplify (2u+3)(u-4)+4u(u-2)

simplify

(2 u + 3) (u - 4) + 4 u (u - 2)

6 u^{2} - 13 u - 12

Solution steps

(2 u + 3) (u - 4) + 4 u (u - 2)

Expand

(2 u + 3) (u - 4) : 2 u^{2} - 5 u - 12

= 2 u^{2} - 5 u - 12 + 4 u (u - 2)

Expand

4 u (u - 2) : 4 u^{2} - 8 u

= 2 u^{2} - 5 u - 12 + 4 u^{2} - 8 u

Group like terms

= 2 u^{2} + 4 u^{2} - 5 u - 8 u - 12

Add similar elements:

2 u^{2} + 4 u^{2} = 6 u^{2}

= 6 u^{2} - 5 u - 8 u - 12

Add similar elements:

- 5 u - 8 u = - 13 u

= 6 u^{2} - 13 u - 12

\frac{x + 1}{x ^{2} - 2 x - 3}

(x - 11) (x + 11)

\frac{b - 1}{b + 2 - \frac{b ^{2} + 2}{b - \frac{b - 2}{b + 1}}}

3 (3 x)

4 (x + 1)^{2}

What is (2u+3)(u-4)+4u(u-2) ?
The solution to (2u+3)(u-4)+4u(u-2) is 6u^2-13u-12