What are the solutions to the equation x^2+x^2=2 ?

The solutions to the equation x^2+x^2=2 are x=1,x=-1

Find the zeros of x^2+x^2=2

The zeros of x^2+x^2=2 are x=1,x=-1

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x^{2} + x^{2} = 2

x = 1, x = - 1

Solution steps

x^{2} + x^{2} = 2

Add similar elements:

x^{2} + x^{2} = 2 x^{2}

2 x^{2} = 2

Divide both sides by

2

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

- 3 x^{2} = - 363

- 6 \leq x \leq 2

- 12 \leq - 3 x + 3 < - 6

3 x \geq 6

\frac{( x ^{2} - 169 )}{x - 13} - 13 < 0.02

What are the solutions to the equation x^2+x^2=2 ?
The solutions to the equation x^2+x^2=2 are x=1,x=-1
Find the zeros of x^2+x^2=2
The zeros of x^2+x^2=2 are x=1,x=-1