What are the solutions to the equation 5x^2+25x-1500=0 ?

The solutions to the equation 5x^2+25x-1500=0 are x=15,x=-20

Find the zeros of 5x^2+25x-1500=0

The zeros of 5x^2+25x-1500=0 are x=15,x=-20

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5 x^{2} + 25 x - 1500 = 0

x = 15, x = - 20

Solution steps

5 x^{2} + 25 x - 1500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 5 ( - 1500 )}{2 \cdot 5}

2 5^{2} - 4 \cdot 5 (- 1500) = 175

x_{1, 2} = \frac{- 25 \pm 175}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 25 + 175}{2 \cdot 5}, x_{2} = \frac{- 25 - 175}{2 \cdot 5}

x = \frac{- 25 + 175}{2 \cdot 5} : 15

x = \frac{- 25 - 175}{2 \cdot 5} : - 20

The solutions to the quadratic equation are:

x = 15, x = - 20

4 x^{2} - 28 x + 24 = 0

(x + 4) (x + 9) (5 - x) \leq 0

\frac{1}{3} x^{2} - \frac{1}{9} x - \frac{10}{9} = 0

(- 3 + 6 i)^{2}

9 x^{2} + 12 x - 5

What are the solutions to the equation 5x^2+25x-1500=0 ?
The solutions to the equation 5x^2+25x-1500=0 are x=15,x=-20
Find the zeros of 5x^2+25x-1500=0
The zeros of 5x^2+25x-1500=0 are x=15,x=-20