What is ((4x^{-2}y^3)/(xy^{-4)})^{-2} ?

The solution to ((4x^{-2}y^3)/(xy^{-4)})^{-2} is (x^6)/(16y^{14)}

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simplify ((4x^{-2}y^3)/(xy^{-4)})^{-2}

simplify

(\frac{4 x ^{- 2} y ^{3}}{x y ^{- 4}})^{- 2}

\frac{x ^{6}}{16 y ^{14}}

Solution steps

(\frac{4 x ^{- 2} y ^{3}}{x y ^{- 4}})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{4 x ^{- 2} y ^{3}}{x y ^{- 4}})^{- 2} = \frac{1}{( \frac{4 x ^{- 2} y ^{3}}{x y ^{- 4}} ) ^{2}}

= \frac{1}{( \frac{4 x ^{- 2} y ^{3}}{x y ^{- 4}} ) ^{2}}

Simplify

(\frac{4 x ^{- 2} y ^{3}}{x y ^{- 4}})^{2} : \frac{16 y ^{14}}{x ^{6}}

= \frac{1}{\frac{16 y ^{14}}{x ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{6}}{16 y ^{14}}

a^{2} + 14 a - 51 = 0

(\frac{x}{4})^{2}

(- \frac{1}{4})^{- 3}

21 6^{\frac{1}{3}}

4.5 c - 2.8 = 3 (1.5 c - 1.9)

What is ((4x^{-2}y^3)/(xy^{-4)})^{-2} ?
The solution to ((4x^{-2}y^3)/(xy^{-4)})^{-2} is (x^6)/(16y^{14)}