What are the solutions to the equation 3x^2+6x=x+2 ?

The solutions to the equation 3x^2+6x=x+2 are x= 1/3 ,x=-2

Find the zeros of 3x^2+6x=x+2

The zeros of 3x^2+6x=x+2 are x= 1/3 ,x=-2

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3 x^{2} + 6 x = x + 2

x = \frac{1}{3}, x = - 2

Decimal Notation

x = 0.33333 \dots, x = - 2

Solution steps

3 x^{2} + 6 x = x + 2

Move

2

to the left side

3 x^{2} + 6 x - 2 = x

Move

x

to the left side

3 x^{2} + 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 2) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot 3}, x_{2} = \frac{- 5 - 7}{2 \cdot 3}

x = \frac{- 5 + 7}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 5 - 7}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 2

- 6 (x - 1) - 7 = - 7 x + 2

\frac{x}{2} - 1 \leq \frac{5 x}{2} - 3

\frac{x}{2} - 9 < 12

\frac{3 x - 24}{3} + 7 = 13

i^{49}

What are the solutions to the equation 3x^2+6x=x+2 ?
The solutions to the equation 3x^2+6x=x+2 are x= 1/3 ,x=-2
Find the zeros of 3x^2+6x=x+2
The zeros of 3x^2+6x=x+2 are x= 1/3 ,x=-2