What are the solutions to the equation 5x^2-6x-1=0 ?

The solutions to the equation 5x^2-6x-1=0 are x=(3+sqrt(14))/5 ,x=(3-sqrt(14))/5

Find the zeros of 5x^2-6x-1=0

The zeros of 5x^2-6x-1=0 are x=(3+sqrt(14))/5 ,x=(3-sqrt(14))/5

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5 x^{2} - 6 x - 1 = 0

x = \frac{3 + 14}{5}, x = \frac{3 - 14}{5}

Decimal Notation

x = 1.34833 \dots, x = - 0.14833 \dots

Solution steps

5 x^{2} - 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

(- 6)^{2} - 4 \cdot 5 (- 1) = 214

x_{1, 2} = \frac{- ( - 6 ) \pm 2 14}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 14}{2 \cdot 5}, x_{2} = \frac{- ( - 6 ) - 2 14}{2 \cdot 5}

x = \frac{- ( - 6 ) + 2 14}{2 \cdot 5} : \frac{3 + 14}{5}

x = \frac{- ( - 6 ) - 2 14}{2 \cdot 5} : \frac{3 - 14}{5}

The solutions to the quadratic equation are:

x = \frac{3 + 14}{5}, x = \frac{3 - 14}{5}

1 - \frac{x}{2} + x = 3 x - 4

- \frac{5}{4} - (- \frac{1}{3})

6 a^{2} - 3.6 a = 0

5 ∣ 2 x - 7 ∣ = 25

- 3 \leq - 3 x + 7 < 4

What are the solutions to the equation 5x^2-6x-1=0 ?
The solutions to the equation 5x^2-6x-1=0 are x=(3+sqrt(14))/5 ,x=(3-sqrt(14))/5
Find the zeros of 5x^2-6x-1=0
The zeros of 5x^2-6x-1=0 are x=(3+sqrt(14))/5 ,x=(3-sqrt(14))/5