What are the solutions to the equation 0=12x^2-176+484 ?

The solutions to the equation 0=12x^2-176+484 are x=sqrt(77/3)i,x=-sqrt(77/3)i

Find the zeros of 0=12x^2-176+484

The zeros of 0=12x^2-176+484 are x=sqrt(77/3)i,x=-sqrt(77/3)i

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0 = 12 x^{2} - 176 + 484

x = \frac{77}{3} i, x = - \frac{77}{3} i

Solution steps

0 = 12 x^{2} - 176 + 484

Switch sides

12 x^{2} - 176 + 484 = 0

Move

176

to the right side

12 x^{2} + 484 = 176

Move

484

to the right side

12 x^{2} = - 308

Divide both sides by

12

x^{2} = - \frac{77}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{77}{3}, x = - - \frac{77}{3}

- \frac{77}{3} = \frac{77}{3} i

- - \frac{77}{3} = - \frac{77}{3} i

x = \frac{77}{3} i, x = - \frac{77}{3} i

4 - 2 (3 x + 1) = 32

4 y^{4} a + 12 y^{2} a + 10 y^{2} a + 30

\frac{c ^{2} - 5 c}{c ^{2} - 12 c + 36} - \frac{6}{c ^{2} - 12 c + 36}

\frac{- 7}{9} + \frac{- 11}{5}

a^{2} - b^{2} - a + b + (a + b - 1)^{2}

What are the solutions to the equation 0=12x^2-176+484 ?
The solutions to the equation 0=12x^2-176+484 are x=sqrt(77/3)i,x=-sqrt(77/3)i
Find the zeros of 0=12x^2-176+484
The zeros of 0=12x^2-176+484 are x=sqrt(77/3)i,x=-sqrt(77/3)i