What are the solutions to the equation 2x^2+71=-163 ?

The solutions to the equation 2x^2+71=-163 are x=3sqrt(13)i,x=-3sqrt(13)i

Find the zeros of 2x^2+71=-163

The zeros of 2x^2+71=-163 are x=3sqrt(13)i,x=-3sqrt(13)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 71 = - 163

x = 313 i, x = - 313 i

Solution steps

2 x^{2} + 71 = - 163

Move

71

to the right side

2 x^{2} = - 234

Divide both sides by

2

x^{2} = - 117

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 117, x = - - 117

- 117 = 313 i

- - 117 = - 313 i

x = 313 i, x = - 313 i

8 ∣ y - 4 ∣ \geq 82

3 x^{2} - 4 x - 1 = 0

- 3 (1 - 4 x) + 4 (1 - 2 x) = 4 x + 1

3 u + 5 \geq 11

(5 x)^{\frac{1}{3}}

What are the solutions to the equation 2x^2+71=-163 ?
The solutions to the equation 2x^2+71=-163 are x=3sqrt(13)i,x=-3sqrt(13)i
Find the zeros of 2x^2+71=-163
The zeros of 2x^2+71=-163 are x=3sqrt(13)i,x=-3sqrt(13)i