What are the solutions to the equation x^2+11x=4 ?

The solutions to the equation x^2+11x=4 are x=(-11+sqrt(137))/2 ,x=(-11-sqrt(137))/2

Find the zeros of x^2+11x=4

The zeros of x^2+11x=4 are x=(-11+sqrt(137))/2 ,x=(-11-sqrt(137))/2

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x^{2} + 11 x = 4

x = \frac{- 11 + 137}{2}, x = \frac{- 11 - 137}{2}

Decimal Notation

x = 0.35234 \dots, x = - 11.35234 \dots

Solution steps

x^{2} + 11 x = 4

Move

4

to the left side

x^{2} + 11 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot (- 4) = 137

x_{1, 2} = \frac{- 11 \pm 137}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 137}{2 \cdot 1}, x_{2} = \frac{- 11 - 137}{2 \cdot 1}

x = \frac{- 11 + 137}{2 \cdot 1} : \frac{- 11 + 137}{2}

x = \frac{- 11 - 137}{2 \cdot 1} : \frac{- 11 - 137}{2}

The solutions to the quadratic equation are:

x = \frac{- 11 + 137}{2}, x = \frac{- 11 - 137}{2}

- 1.2 (5)^{2} + 9.6 (5)

(7 X - 1)^{2} = 1

\frac{1}{12} (3 a - 6 b)

3 x^{3} - 24 x^{2} y + 48 x y^{2}

6 y - 9 + 2 y - 5 = - 8 y + 17 + 4 y

What are the solutions to the equation x^2+11x=4 ?
The solutions to the equation x^2+11x=4 are x=(-11+sqrt(137))/2 ,x=(-11-sqrt(137))/2
Find the zeros of x^2+11x=4
The zeros of x^2+11x=4 are x=(-11+sqrt(137))/2 ,x=(-11-sqrt(137))/2