What are the solutions to the equation 3x^2+18x=-12 ?

The solutions to the equation 3x^2+18x=-12 are x=-3+sqrt(5),x=-3-sqrt(5)

Find the zeros of 3x^2+18x=-12

The zeros of 3x^2+18x=-12 are x=-3+sqrt(5),x=-3-sqrt(5)

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3 x^{2} + 18 x = - 12

x = - 3 + 5, x = - 3 - 5

Decimal Notation

x = - 0.76393 \dots, x = - 5.23606 \dots

Solution steps

3 x^{2} + 18 x = - 12

Move

12

to the left side

3 x^{2} + 18 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

1 8^{2} - 4 \cdot 3 \cdot 12 = 65

x_{1, 2} = \frac{- 18 \pm 6 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 18 + 6 5}{2 \cdot 3}, x_{2} = \frac{- 18 - 6 5}{2 \cdot 3}

x = \frac{- 18 + 6 5}{2 \cdot 3} : - 3 + 5

x = \frac{- 18 - 6 5}{2 \cdot 3} : - 3 - 5

The solutions to the quadratic equation are:

x = - 3 + 5, x = - 3 - 5

\frac{9}{5} - 1

- 3 (\frac{1}{2})^{2}

(- \frac{1}{2})^{3}

2 x (1 + \frac{1}{2} x) = x (\frac{1}{2} x + 1)

∣ 2 x + 3 ∣ < 10 ∣ x ∣

What are the solutions to the equation 3x^2+18x=-12 ?
The solutions to the equation 3x^2+18x=-12 are x=-3+sqrt(5),x=-3-sqrt(5)
Find the zeros of 3x^2+18x=-12
The zeros of 3x^2+18x=-12 are x=-3+sqrt(5),x=-3-sqrt(5)