What is (2+9i)/(-3-i) ?

The solution to (2+9i)/(-3-i) is -3/2-5/2 i

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simplify (2+9i)/(-3-i)

simplify

\frac{2 + 9 i}{- 3 - i}

- \frac{3}{2} - \frac{5}{2} i

Solution steps

\frac{2 + 9 i}{- 3 - i}

Multiply by the conjugate

\frac{- 3 + i}{- 3 + i}

= \frac{( 2 + 9 i ) ( - 3 + i )}{( - 3 - i ) ( - 3 + i )}

Simplify

\frac{( 2 + 9 i ) ( - 3 + i )}{( - 3 - i ) ( - 3 + i )} : \frac{- 15 - 25 i}{10}

= \frac{- 15 - 25 i}{10}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{- 15}{10} + \frac{- 25}{10} i

Simplify

\frac{- 15}{10} + \frac{- 25}{10} i : - \frac{3}{2} - \frac{5}{2} i

= - \frac{3}{2} - \frac{5}{2} i

\frac{3}{5} \cdot 3

3 (1 + x) - 5 = 3 x - 2

(6 x^{3} y) (x^{2})^{- 2}

2 y - 8 + x y - 4 x

c^{2} + 15 c + 44