What are the solutions to the equation 3x^2-5x=-2 ?

The solutions to the equation 3x^2-5x=-2 are x=1,x= 2/3

Find the zeros of 3x^2-5x=-2

The zeros of 3x^2-5x=-2 are x=1,x= 2/3

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3 x^{2} - 5 x = - 2

x = 1, x = \frac{2}{3}

Solution steps

3 x^{2} - 5 x = - 2

Move

2

to the left side

3 x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 \cdot 2 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 3}

x = \frac{- ( - 5 ) + 1}{2 \cdot 3} : 1

x = \frac{- ( - 5 ) - 1}{2 \cdot 3} : \frac{2}{3}

The solutions to the quadratic equation are:

x = 1, x = \frac{2}{3}

∣ 2 x - 1 ∣ < x^{2} - x + \frac{1}{∣ - 4 ∣} + 1

x^{2} + 3 x - 54

9 k^{2}

0 = - x^{2} + 44 x + 1

\frac{k}{6.5} = - 15.7

What are the solutions to the equation 3x^2-5x=-2 ?
The solutions to the equation 3x^2-5x=-2 are x=1,x= 2/3
Find the zeros of 3x^2-5x=-2
The zeros of 3x^2-5x=-2 are x=1,x= 2/3