What are the solutions to the equation 3x^2-6x=29 ?

The solutions to the equation 3x^2-6x=29 are x=(3+4sqrt(6))/3 ,x=(3-4sqrt(6))/3

Find the zeros of 3x^2-6x=29

The zeros of 3x^2-6x=29 are x=(3+4sqrt(6))/3 ,x=(3-4sqrt(6))/3

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3 x^{2} - 6 x = 29

x = \frac{3 + 4 6}{3}, x = \frac{3 - 4 6}{3}

Solution steps

3 x^{2} - 6 x = 29

Move

29

to the left side

3 x^{2} - 6 x - 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 29 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 29) = 86

x_{1, 2} = \frac{- ( - 6 ) \pm 8 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 8 6}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 8 6}{2 \cdot 3}

x = \frac{- ( - 6 ) + 8 6}{2 \cdot 3} : \frac{3 + 4 6}{3}

x = \frac{- ( - 6 ) - 8 6}{2 \cdot 3} : \frac{3 - 4 6}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 4 6}{3}, x = \frac{3 - 4 6}{3}

\frac{130 π}{180}

5 x^{2} + x + 4 = 0

(2 x)^{- 3}

\frac{3}{5} + \frac{3}{2}

0 = 144 t - 16 t^{2}

What are the solutions to the equation 3x^2-6x=29 ?
The solutions to the equation 3x^2-6x=29 are x=(3+4sqrt(6))/3 ,x=(3-4sqrt(6))/3
Find the zeros of 3x^2-6x=29
The zeros of 3x^2-6x=29 are x=(3+4sqrt(6))/3 ,x=(3-4sqrt(6))/3