What is the answer to 1/3 (y+7)=3(y-1) ?

The answer to 1/3 (y+7)=3(y-1) is y=2

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1/3 (y+7)=3(y-1)

\frac{1}{3} (y + 7) = 3 (y - 1)

y = 2

Solution steps

\frac{1}{3} (y + 7) = 3 (y - 1)

Expand

\frac{1}{3} (y + 7) : \frac{1}{3} y + \frac{7}{3}

Expand

3 (y - 1) : 3 y - 3

\frac{1}{3} y + \frac{7}{3} = 3 y - 3

Move

\frac{7}{3}

to the right side

\frac{1}{3} y = 3 y - \frac{16}{3}

Move

3 y

to the left side

- \frac{8}{3} y = - \frac{16}{3}

Multiply both sides by

3

- 8 y = - 16

Divide both sides by

- 8

y = 2

\frac{1}{2} + \frac{1}{3} \div (\frac{1}{2} - \frac{1}{3})

x^{8} \cdot x^{3}

\frac{3}{4} \cdot \frac{1}{3}

- 2 \cdot \frac{3}{2}

\frac{x - 5}{x + 5} > 0