What are the solutions to the equation -7y^2+7y+1=0 ?

The solutions to the equation -7y^2+7y+1=0 are y=-(-7+sqrt(77))/(14),y=(7+sqrt(77))/(14)

Find the zeros of -7y^2+7y+1=0

The zeros of -7y^2+7y+1=0 are y=-(-7+sqrt(77))/(14),y=(7+sqrt(77))/(14)

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- 7 y^{2} + 7 y + 1 = 0

y = - \frac{- 7 + 77}{14}, y = \frac{7 + 77}{14}

Decimal Notation

y = - 0.12678 \dots, y = 1.12678 \dots

Solution steps

- 7 y^{2} + 7 y + 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 7 ) \cdot 1}{2 ( - 7 )}

7^{2} - 4 (- 7) \cdot 1 = 77

y_{1, 2} = \frac{- 7 \pm 77}{2 ( - 7 )}

Separate the solutions

y_{1} = \frac{- 7 + 77}{2 ( - 7 )}, y_{2} = \frac{- 7 - 77}{2 ( - 7 )}

y = \frac{- 7 + 77}{2 ( - 7 )} : - \frac{- 7 + 77}{14}

y = \frac{- 7 - 77}{2 ( - 7 )} : \frac{7 + 77}{14}

The solutions to the quadratic equation are:

y = - \frac{- 7 + 77}{14}, y = \frac{7 + 77}{14}

6 z - 3 \geq - 3 and 5 z + 4 \geq 19

(0.5)^{3}

- 7 (x + 5) + 1 = 15

∣ - 2 + 4 i ∣

2 x^{2} + 2 x = 60

What are the solutions to the equation -7y^2+7y+1=0 ?
The solutions to the equation -7y^2+7y+1=0 are y=-(-7+sqrt(77))/(14),y=(7+sqrt(77))/(14)
Find the zeros of -7y^2+7y+1=0
The zeros of -7y^2+7y+1=0 are y=-(-7+sqrt(77))/(14),y=(7+sqrt(77))/(14)