What are the solutions to the equation 3x^2+5x-10=0 ?

The solutions to the equation 3x^2+5x-10=0 are x=(-5+sqrt(145))/6 ,x=(-5-sqrt(145))/6

Find the zeros of 3x^2+5x-10=0

The zeros of 3x^2+5x-10=0 are x=(-5+sqrt(145))/6 ,x=(-5-sqrt(145))/6

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3 x^{2} + 5 x - 10 = 0

x = \frac{- 5 + 145}{6}, x = \frac{- 5 - 145}{6}

Decimal Notation

x = 1.17359 \dots, x = - 2.84026 \dots

Solution steps

3 x^{2} + 5 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 10) = 145

x_{1, 2} = \frac{- 5 \pm 145}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 145}{2 \cdot 3}, x_{2} = \frac{- 5 - 145}{2 \cdot 3}

x = \frac{- 5 + 145}{2 \cdot 3} : \frac{- 5 + 145}{6}

x = \frac{- 5 - 145}{2 \cdot 3} : \frac{- 5 - 145}{6}

The solutions to the quadratic equation are:

x = \frac{- 5 + 145}{6}, x = \frac{- 5 - 145}{6}

(\frac{1}{81})^{\frac{3}{4}}

100 \cdot 0.0 4^{2} = 0.0032 \cdot v^{2} + 100 \cdot 0.0 1^{2}

3 \cdot 18

9 x (2 x + 1) = 5

(\frac{1 + i}{1 - i})^{2}

What are the solutions to the equation 3x^2+5x-10=0 ?
The solutions to the equation 3x^2+5x-10=0 are x=(-5+sqrt(145))/6 ,x=(-5-sqrt(145))/6
Find the zeros of 3x^2+5x-10=0
The zeros of 3x^2+5x-10=0 are x=(-5+sqrt(145))/6 ,x=(-5-sqrt(145))/6