What are the solutions to the equation (x/2)^2+12^2=15^2 ?

The solutions to the equation (x/2)^2+12^2=15^2 are x=18,x=-18

Find the zeros of (x/2)^2+12^2=15^2

The zeros of (x/2)^2+12^2=15^2 are x=18,x=-18

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(\frac{x}{2})^{2} + 1 2^{2} = 1 5^{2}

x = 18, x = - 18

Solution steps

(\frac{x}{2})^{2} + 1 2^{2} = 1 5^{2}

Move

1 2^{2}

to the right side

(\frac{x}{2})^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

\frac{x}{2} = 81 : x = 18

Solve

\frac{x}{2} = - 81 : x = - 18

The solutions to the quadratic equation are:

x = 18, x = - 18

\frac{( \frac{2}{5} ) ^{4}}{( - \frac{1}{3} ) ^{9} ( \frac{3}{5} ) ^{4}}

\frac{1}{4 3}

3 + (- 7)

33 = 2 x + 17

6 (\frac{1}{3})^{3}

What are the solutions to the equation (x/2)^2+12^2=15^2 ?
The solutions to the equation (x/2)^2+12^2=15^2 are x=18,x=-18
Find the zeros of (x/2)^2+12^2=15^2
The zeros of (x/2)^2+12^2=15^2 are x=18,x=-18