What are the solutions to the equation 2x^2+7x-5=0 ?

The solutions to the equation 2x^2+7x-5=0 are x=(-7+sqrt(89))/4 ,x=(-7-sqrt(89))/4

Find the zeros of 2x^2+7x-5=0

The zeros of 2x^2+7x-5=0 are x=(-7+sqrt(89))/4 ,x=(-7-sqrt(89))/4

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2 x^{2} + 7 x - 5 = 0

x = \frac{- 7 + 89}{4}, x = \frac{- 7 - 89}{4}

Decimal Notation

x = 0.60849 \dots, x = - 4.10849 \dots

Solution steps

2 x^{2} + 7 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 5) = 89

x_{1, 2} = \frac{- 7 \pm 89}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 89}{2 \cdot 2}, x_{2} = \frac{- 7 - 89}{2 \cdot 2}

x = \frac{- 7 + 89}{2 \cdot 2} : \frac{- 7 + 89}{4}

x = \frac{- 7 - 89}{2 \cdot 2} : \frac{- 7 - 89}{4}

The solutions to the quadratic equation are:

x = \frac{- 7 + 89}{4}, x = \frac{- 7 - 89}{4}

\frac{6 2}{2}

- 3 x^{2} + 2 = 0

6 x^{2} - 30 = 0

\frac{a ^{2}}{\frac{4}{5} - \frac{4}{a}}

What are the solutions to the equation 2x^2+7x-5=0 ?
The solutions to the equation 2x^2+7x-5=0 are x=(-7+sqrt(89))/4 ,x=(-7-sqrt(89))/4
Find the zeros of 2x^2+7x-5=0
The zeros of 2x^2+7x-5=0 are x=(-7+sqrt(89))/4 ,x=(-7-sqrt(89))/4