What are the solutions to the equation 12x^2+20x+3=0 ?

The solutions to the equation 12x^2+20x+3=0 are x=-1/6 ,x=-3/2

Find the zeros of 12x^2+20x+3=0

The zeros of 12x^2+20x+3=0 are x=-1/6 ,x=-3/2

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12 x^{2} + 20 x + 3 = 0

x = - \frac{1}{6}, x = - \frac{3}{2}

Solution steps

12 x^{2} + 20 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 12 \cdot 3}{2 \cdot 12}

2 0^{2} - 4 \cdot 12 \cdot 3 = 16

x_{1, 2} = \frac{- 20 \pm 16}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 20 + 16}{2 \cdot 12}, x_{2} = \frac{- 20 - 16}{2 \cdot 12}

x = \frac{- 20 + 16}{2 \cdot 12} : - \frac{1}{6}

x = \frac{- 20 - 16}{2 \cdot 12} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{6}, x = - \frac{3}{2}

\frac{5}{6} \cdot 3

\frac{36 x ^{- 2} y ^{2}}{15 z ^{- 3}}

- 2 = lo g_{7} (\frac{1}{49})

1500 - 250 \cdot \frac{1 - 1.0 6 ^{- 7}}{0.06}

x (x + 12) = (x + 6)^{2}

What are the solutions to the equation 12x^2+20x+3=0 ?
The solutions to the equation 12x^2+20x+3=0 are x=-1/6 ,x=-3/2
Find the zeros of 12x^2+20x+3=0
The zeros of 12x^2+20x+3=0 are x=-1/6 ,x=-3/2