What are the solutions to the equation -3=(x-2)^2-7 ?

The solutions to the equation -3=(x-2)^2-7 are x=4,x=0

Find the zeros of -3=(x-2)^2-7

The zeros of -3=(x-2)^2-7 are x=4,x=0

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- 3 = (x - 2)^{2} - 7

x = 4, x = 0

Solution steps

- 3 = (x - 2)^{2} - 7

Switch sides

(x - 2)^{2} - 7 = - 3

Move

7

to the right side

(x - 2)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 4 : x = 4

Solve

x - 2 = - 4 : x = 0

The solutions to the quadratic equation are:

x = 4, x = 0

21

2 x z - 6 x y + 2 yz - 6 y^{2}

m^{2} - 6 m + 9 = 0

\frac{2}{5} + \frac{4}{3}

7 p < 4 p + 9

What are the solutions to the equation -3=(x-2)^2-7 ?
The solutions to the equation -3=(x-2)^2-7 are x=4,x=0
Find the zeros of -3=(x-2)^2-7
The zeros of -3=(x-2)^2-7 are x=4,x=0