What are the solutions to the equation z^2+6z-7=0 ?

The solutions to the equation z^2+6z-7=0 are z=1,z=-7

Find the zeros of z^2+6z-7=0

The zeros of z^2+6z-7=0 are z=1,z=-7

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z^{2} + 6 z - 7 = 0

z = 1, z = - 7

Solution steps

z^{2} + 6 z - 7 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 7) = 8

z_{1, 2} = \frac{- 6 \pm 8}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 6 + 8}{2 \cdot 1}, z_{2} = \frac{- 6 - 8}{2 \cdot 1}

z = \frac{- 6 + 8}{2 \cdot 1} : 1

z = \frac{- 6 - 8}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

z = 1, z = - 7

\frac{1}{\frac{1}{15} + \frac{1}{10} + \frac{1}{30}}

3 (t)^{2} - 27 = 0

15 = 5 + 4 (2 d - 3)

\frac{8 !}{( 8 - 6 ) ! 6 !}

i^{2016}

What are the solutions to the equation z^2+6z-7=0 ?
The solutions to the equation z^2+6z-7=0 are z=1,z=-7
Find the zeros of z^2+6z-7=0
The zeros of z^2+6z-7=0 are z=1,z=-7